Published by:
CGP EDU Academic Team
Published on: August 13, 2026
In triangle ABC, the value of 
a r · b n–r · cos
(rB – (n – r) A) is equal to -
Text Solution
Verified by ExpertsThe correct answer is:
A
a r · b n–r · cos (rB – (n – r) A)
= Re 
= Re 
= Re (a e iB + b . e –iA ) n
= Re (a cos B + ia sin B + b cos A – ib sin A) n
= (a cos B + b cos A) n = c n ..
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